the length of one side of a rectangle is 7 cm. what should the length of the other side be so the perimeter of the rectangle is less than the perimeter of a square with a side of 6cm?

4cm

Step-by-step explanation: When solving to find the perimeter of a shape, we multiply the side of the shape by another side (length x width x 2). If it is a quadrilateral (a shape with four sides and angles).

1) we know the length of the rectangle is 7cm and the perimeter has to be less then a perimeter of a square with a 6cm side. We have to find the perimeter of the square first. So we have to solve 2 x 6 + 6 which is 24cm.

2) We now know the perimeter of the square is 24cm so the rectangles perimeter has to be less. One of the rectangles sides is 7cm so the next side has to be less than 7cm and have the product of less than 24. So 2 x 7 + 4 in this case it equals 22 less than 24 and also 4cm is less than 7cm.

i would need to see the dot plot : )

set each factor equal to 0

4x-3 = 0

2x-1 = 0

solve for x.

4x-3=0

4x=3

x= 3/4

solve for x. 

2x-1= 0

2x= 1

x= 1/2

your answer should be 1/2 is less than or equal to x and 3/4 is greater than or equal to x