HELP PLS What are the roots of the equation?
x^2(4x - 5) (7x - 13) = 0

i need the steps of how to get the answer

If the answer is wrong delete it

Step-by-step explanation:

STEP  1:

x2 • (4x - 5) • (7x - 13)  = 0  

STEP  2:

 x2 • (4x - 5) • (7x - 13)  = 0  

STEP 3:

Theory - Roots of a product

3.1    A product of several terms equals zero.  

When a product of two or more terms equals zero, then at least one of the terms must be zero.  

We shall now solve each term = 0 separately  

In other words, we are going to solve as many equations as there are terms in the product  

Any solution of term = 0 solves product = 0 as well.

Solving a Single Variable Equation:

3.2      Solve  :    x2 = 0  

Solution is  x2 = 0

Solving a Single Variable Equation:

3.3      Solve  :    4x-5 = 0  

Add  5  to both sides of the equation :  

                     4x = 5

Divide both sides of the equation by 4:

                    x = 5/4 = 1.250

Solving a Single Variable Equation:

3.4      Solve  :    7x-13 = 0  

Add  13  to both sides of the equation :  

                     7x = 13

Divide both sides of the equation by 7:

                    x = 13/7 = 1.857

Three solutions were found :

x = 13/7 = 1.857

x = 5/4 = 1.250

x2 = 0

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step-by-step explanation:

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if you need just tell me and i will come to the rescue.

step-by-step explanation: