The table shows the number of students in four schools who own computers. Which school has the greatest percent of students who own computers? 90/270, 56/100, 110/150, 125/500 HELP NEEDED QUICK

110/150

Step-by-step explanation:

125/500 is smallest, since you can imagine the difference from 125 to 500 is much larger compared to the others! Then, 90/270 is second smallest, because 9/27 is simply one third. You can tell that 125/500 is smaller than one third, because 125x3 is less than 500. After that, we only have 56/100 and 110/150. We need the denominators to be the same.

56/100

110/150

100 is two thirds of 150. This means that we must divide the numerator by 2 and multiply it by three to balance the common denominator. 56/2 then x3 is 84, which is less than 110.

56/100 = 84/150

84/150 < 110/150

Therefore the largest fraction is the 110/150 school.

answer is the third choice:

3x^5+4x^4+x^3+2x^2-10x-7=0

step-by-step explanation:

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204