A triangle has a perimeter of 32.4 kilometres. Two of the sides measure 10.8 kilometres and 10.8 kilometres. What is the length of the third side?

10.8 kilometers

Step-by-step explanation:

Perimeter of a triangle equation is P (perimeter)= a+b+c

put 32.4 of the left side of the equation as it is the answer for the perimeter and replace and and b with your first 2 side legnths like this

32.4= 10.8+ 10.8+c

Now we must solve for the unknown side legnth c. To do this we must simplify the right side of the equation first by adding 10.8+ 10.8

32.4= 21.6+c

Now we can subtract 21.6 from the left side to solve for c

10.8=c

Therefore the third side is 10.8 kilometers

10.8 km

Step-by-step explanation:  A triangle has three sides:  a, b, and c

The perimeter is a+b+c and is a total of 32.4 km.   We know a=10.8 km and b = 10.8 km.

10.8 km + 10.8 km + c = 32.4 km

21.6km + c =  32.4 km

c = 10.8 km

region b will make the inequalities y < 2x + 1 and y > -x - 2 true ⇒ answer a

step-by-step explanation:

* lets study the graph and the inequality to solve the question

- the inequality y > -x - 2

∵ the form of the inequality is y > mx + c , m is the slope of the line

  and c is the y-intercept (the line intersect y-axis at point (0 , c)

∴ c = -2 that means the line intersect the y-axis at point (0 , -2)

∵ the sign of the inequality is >

∴ we shad the part over the line

  region a and b

- the inequality y < 2x + 1

∵ the form of the inequality is y > mx + c , m is the slope of the line

  and c is the y-intercept (the line intersect y-axis at point (0 , c)

∴ c = 1 that means the line intersect the y-axis at point (0 , 1)

∵ the sign of the inequality is <

∴ we shad the part under the line

  region b and c

∵ the common region between the two lines is region b

∴ region b will make the inequalities y < 2x + 1 and y > -x - 2 true