Write an equation with the smallest possible degree for the function graphed attached.

f(x) = 1/18(x + 2)(x - 1)²(x - 3)³

Step-by-step explanation:

Analyzing the graph:

It's even degree as overall U-shapedZeros at -2, 1, 3. It gives us factors of (x + 2), (x - 1) and (x - 3)Touches the x-axis at x = 1, its indication of (x - 1) is of degree 2.Touches and intersects the x- axis at x = 3, its indication of (x - 3) is degree 3.

According to the above observations we have:

f(x) = a(x + 2)(x - 1)²(x - 3)³

Since we don't see the exact minimum of function we assume a = 1/18 is approximately what we need.

So the equation is:

f(x) = 1/18(x + 2)(x - 1)²(x - 3)³

See attached graph