Help anyone can help me do this question, I will mark brainlest.

Given information

Length AB = 6m

Breadth BC = 4m

The area of PQRS is  twice the area of ABCD

Firstly find the area of rectangle ABCD

Area of ABCD= Length × Breadth

Area of ABCD= 6 × 4

Area of ABCD = 24 m²

We know that the area of rectangle PQRS is twice the area of rectangle  ABCD so we simply double the area of rectangle ABCD

24m² × 2 = 48m²

We need to find 2 numbers which when multiplied give 48 however the 2 numbers that are chosen must be the same amount greater that the lengths of ABCD and divisible by 2 because the path is uniform.

8 × 6 = 48

8 - 6 = 2

6 - 2 = 2

Therefore the length of PQ is 8m and the length of QR is 6m

the first one is x^2+2x+2

the second one is x^2+4

the last one is x^2-4x+8