Sandy has $4,000 invested in stocks and bonds. Last year, she earned 8% interest on the stocks and 6% interest on the bonds. At the end of the year, Sandy received

a check for $270. This was her annual income from the stocks and bonds. Which

system of equations below will determine s, the amount of money Sandy has

invested in stocks, and b, the amount invested in bonds?

F S + b = 4,000

Hs + b = 270

0.08s + 0.06b = 270

4,000

+ b = 270

S

Gs + b = 270

4,000 270 = s

Js + b = 4,000

0.06s + 0.08b = 270

.

step-by-step explanation:

step-by-step explanation:

in which figure is point g a centroid

step-by-step explanation:

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

the factor is 2

step-by-step explanation:

let f(x)=8(3^(x−2)+2)

to stretch a graph by 3, it would be 3f(x)

g(x) =3f(x)

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

x     −2     0     2     4     6

f(x) 1/64 1/16   1/4     1     4

1/64 * z * z = 1/16

i multiplies by z twice because it its 2 steps from -2 to 0

1/64 z^2 = 1/16

multiply by 64 to clear the fraction on the left side

1/4 * 64 z^2 =1/16 *64

z^2 = 4

take the square root of each side

sqrt(z^2) = ±sqrt(4)

z = ±2  

we are multiplying by 2 each time.