What is the range of h? Answer choices:
A: -7 ≤ h(x) ≤ 5
B: -3 ≤ h(x) ≤4
C: The h(x)-values -3, -2, 2, and 4
D: The h(x)-values -7, -5, -2, 0, and 5

C: The h(x)-values -3, -2, 2, and 4

Step-by-step explanation:

The range is the values that the output can take

The y values  are -3, -2, 2,4

C: The h(x)-values -3, -2, 2, and 4

let's call the solutions x₁ = (5 - 2√7)/3 and x₂ = (5 + 2√7)/3

then the equation is (x-x₁)(x-x₂) = 0

if you fill that in you get a lot of numbers which you can recognize as ax²+bx+c=0.

step-by-step explanation:

you can see that a=1 (there is just an x²)

b = (-5 -2√7 + 2√7 - 5)/3 = -10/3

c = -2√7)/3 ) * (-5+2√7)/3) = -1/3

so your answer is 3x^2 – 10x – 1 = 0