The product of three consecutive integers is 3360. What is the sum of the three integers?

Step-by-step explanation:

let the integer be x .

three consecutive integers : x, x+1, x+2.

according to the problem,.

Let the first of the 3 consecutive numbers be X.

Therefore the second number is (X + 1)

The third number is therefore (X + 2)

The product of the 3 consecutive numbers is:

( X )( X + 1 )( X + 2 ) = 3360 Equation( 1 )

Expanding Equation ( 1 ) gives

X³ + 3X² + 2X - 3360 = 0 Equation (2)

Solve Equation (2 ) which gives the following values for X

X1 = 14

X2 = - 8.5 + i (12.951834)

X3 = - 8.5 - i (12.951834).

the numbers are 14,15,16.

sum is 14+15+16 = 45.

hope this helps you.

. + λrh() e 1 1 2 4 4 4 4 4 3 4 4 4 4 4 + th−1(− s(x)2 dx ω + λrh−1() e 2 1 2 4 4

step-by-step explanation: