An object dropped from a height of 280 feet will fall according to the equation h(t) =280 - 16t^2, where t is measured in seconds, and h(t) is measured in feet. What is the height of the object after 2 seconds?

How long will it take for the object to hit the ground?

Give your answers as decimal values.

(2,9)

i think thats the answer i checked it on google

step-by-step explanation:

y = | -2(-2) |     →     y = | 4 |     →     y = 4       ⇒   (-2, 4)

y = | -2(-1) |     →     y = | 2 |     →       y =   2       ⇒   (-1, 2)    

y = | -2(0) |     →     y = | 0 |     →       y = 0         ⇒   (0, 0)

y = | -2(1) |   c →     y = | -2 |     →     y =   2         ⇒   (1, 2)    

y = | -2(2) |     →     y = | - 4 |     →     y =   4         ⇒   (2, 4)