Let Q be in the interior of angle POR . Use the Angle Addition Postulate to solve for x. Find the measure of each angle. angle POQ=(1/3x + 1/3)°
angle QOR=(2x+ 4/3)°
angle POR=(5x-1)°

X=1

POQ= 1/3x+1/3= 1/3(1)+1/3=2/3

QOR= 2x +4/3= 2(1)+4/3= 10/3

POR= 5x-1= 5(1)-1= 4

Step-by-step explanation:

the figures below are made out of circles, semicircles, quarter … find the area and the perimeter of each figure and give your answers as a completely simplified exact value in terms of π (no approximations). remember that we'll also have to cut whatever areas we get in half, since we're only dealing im pretty sure that is the right answer

step-by-step explanation:

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v