g (a) Find t0.025,14 (b) Find P(−1.356 < T < 2.179) when ν = 12 degrees of freedom. (c) Find P(−t0.005 < T < t0.01) when ν = 20 degrees of freedom. (d) Given a random sample of size 24 from a normal distribution, X is the sample mean and let T = X−µ S/√ n , find k such that P(k < T < 2.807) = 0.095. (e) What value of tα/2,19 would result in a 99% two-sided CI? (f) What value of tα,24 would result in a 99.9% one-sided CI?

  about 5.6 days

step-by-step explanation:

we can fill the given information into the decay equation and solve for the value of t at which half the sample remains.

the half-life is about 5.6 days.

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

answer: do we write it

step-by-step explanation:

answer: y=0 if that is what u r looking for