A box contains 10 light bulbs, of which 3 are defective and the other 7 work. If two bulbs are drawn in succession without replacement, what is the probability of getting 1 working bulb and 1 defective bulb?

Working: 7/10

defective:3/10

Step-by-step explanation:

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tickets for the harlem globetrotters

show at michigan state university in

2010 cost $16, $23, or, for vip seats, $40.

total revenue = 16x + 23y + 40z

if 9 times as many $16 tickets were sold

as vip tickets,

x = 9z => x – 9z = 0, if 9 times as many $16 tickets were sold

as vip tickets,

x = 9z => x – 9z = 0, sales of all three kinds of tickets would

total $46,575.

16x + 23y + 40z = 46575, how many of each kind of ticket would

have been sold?

solve for x, y and z

x − 9z = 0

x − y − z = 55

16x + 23y + 40z = 46575

x = 1170

y = 985

z = 130

welcome!

i used to know how to do this in 7th but i forget easily

step-by-step explanation: