1-Which transformation would allow you to map Quadrilateral ABCD onto Quadrilateral PQRS? A-Reflection

B-Translation

C-Rotation

D-Dilation

2-How does performing a rigid motion transformation help you prove congruence?

A-In rigid motion side lengths and angle measures are preserved, which creates congruent shapes

B-In rigid motion side lengths are changed but angle measures stay the same

C-You cannot use rigid motion to prove congruence because the shapes may not stay the same size

answer rather than having to add and subtract the measurements of the semi-circle, notice that the semicircle to the left of ad is actually identical in area to the blank semicircle-shaped space to the left of bc. so if we transferred the red semicircle into the blank space, we would end up with a square of side length 24 cm. the area of a square is s^2 = 24^2 = 676 cm^2.

u also answered this so i think u would know but i am here to

put in or use mine

(- 1, 0 )

step-by-step explanation:

an x- intercept is where the function crosses the x- axis.

to find the x- intercept/s look for the value of x when f(x) = 0

from the given table there are 3 values of x where f(x) = 0

when x = - 1, x = 2, x = 3

the one that is listed is (- 1, 0 )