Imagine a college where say 2000 students are taking an intro stat course. Imagine from historical data, that student scores of a final exam can be viewed as approximately normal with a mean of 70 and a sd of 10. Suppose an A grade is considered to be 90 or higher. Now imagine a SRS of 100 students is selected from the group of 2000 students, where we then compute the sample mean of these 100 students.

a. the are of the rectangle is 18.25

b. 18.25 times two is 36.50

rae me : d

the discriminant is 64 + 4*1*12 = 112

this is prime.

step-by-step explanation:

1. 3.4/4

2. 0.8/7

3. 0.5 x 3

4. 0.9 x 6

5. 10.8

6. 2.35

7. 0.567

8. 9.35

9. 0.02

10. 0.06

11. 0.16

12. 0.42

13. 0.63

14. 5.6

15. 8.1

16. 9.9

17. 0.28

18. 0.48

19. 0.27

20. 0.49

21. 0.45

22. 0.72

23. 0.9

24. 0.88

25. 0.75

26. 0.16

27. 0.328

28. 0.495

29. 0.72

30. 1.068

answer:

step-by-step explanation:

here, the total dishes = 10

dishes having meat = 3 ( chicken, meatloaf and hamburger )

thus, the probability of having meat on the chosen dishes = number of dishes having meat / total dishes

=

therefore, the probability of not having meat = 1- the probability of having meat on the chosen dishes

=

=

=

⇒ option b is correct.