How many numbers are there between 99 and 1000 having 7 in the units place?

90

Step-by-step explanation:

7 is in the unit's place. The middle digit can be any one of the 10 digits from 0 to 9. The digit in hundred's place can be any one of the 9 digits from 1 to 9. Therefore by the fundamental principle of counting there are 10 × 9 = 90 numbers between 99 and 1000 having 7 in the unit's place.

there is 90

Step-by-step explanation:

idk bring the function back   im not smart

step-by-step explanation:

hello :

70y^8 + 30y^6 = 2 ( 35 y^8 + 15y^6)

the lenght is : 35 y^8

the width is : 15y^6