Prove that set  A={x∈R:x11+7x5+5–√x3+8x−2(cosx)< ;0}A={x∈R:x11+7x5+5x3+8x−2(cosx)< ;0}    is non-empty and bounded above. Thus, by the completeness axiom, the supremum  supAsupA   exists as a real number.

3 1/3 x 2 3/5 = 8 2/3

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just multiply the first number by the second number to get your answer.

i dont know if you cant find a way its best to actually add all of them start from 105 tho

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answer: b

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