Graphs of the following equations are straight lines EXCEPT? A. 3x+2y=8
B. y=x/2-5
C. X=4y
D. y =x²+3
With explanation please.

D

Step-by-step explanation:

D, because it's a polynomial equation.  This mean the value of y goes up by base factor for every x value.  Take for example, when x is 3, then y is 10.  Also, when x is 4, then y is 17.  Which mean x and y are not linear relationship, but more of an exponential relationship.

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?

δabc ≅ δdcb by sas because

db ≅ ac . . given (side)

bc ≅ bc . . reflexive property (side)

∠dbc ≅ ∠ acb . . alternate interior angles where transversal bc crosses parallel lines bd and ac (included angle)