PLEASE HELP!!! A new Neighborhood Activity Complex is being built-in
Safe Harbor. The perimeter of the rectangular playing field is 230
yards. The length of the field is 8 yards less than double the width. What are the dimensions of the playing field?

Step-by-step explanation:

L = 2W - 8

P = 230 yd

P = 2×(L+W)

230 = 2× (2W - 8 + W)

230 = 2× (3W-8)

230 = 6W-16

6W= 230+16

6W = 246

W = 246/6

W = 41

L = 2(41) -8

= 82-8

= 74

so, the dimensions of the playing field:

the length = 74 yd

the wide = 41 yd

step-by-step explanation:

in the absence of parentheses, i will have to make some assumptions:   i interpret your (3x+5/y^6)(4y^3/5)​ to mean:

3x + 5     4y^(3/5)       (3x + 5)(4)

* =

    y^6             1               y^(6-3/5)

if this is not what you expected, repost your question using parentheses to indicate whether you meant

4y^3

    or   4y^(3/5)

    5

14

step-by-step explanation: