a corner of a fenced yrad forms a right angle. can you place a 12 foot long board across the corner to form a right angle for which the leg lengths are whole numbers?

72

Step-by-step explanation:

So draw a square and make an right angle in one of  the squares  corners! so basically what ever is on one side it's on the other side so theirs two 12 so 144 the dived my 2 which is 72!

I don't remember this sorry!

so firstly, we need to isolate the y variables to be able to solve these inequalities. firstly, add 0.5x on both sides of the first inequality and subtract 1.5x on both sides of the second inequality:

now since the slope is positive for the first inequality, this means that the line going upwards belongs to the first inequality, and the line going downwards belongs to the second inequality.

next, since y ≥ in the first inequality, this means that the shaded region will be above the first inequality's line, thus shading regions a and b.

next, since y ≤ in the second inequality, this means that the shaded region is going to be below this line, thus shading regions a and c.

since both lines shade region a, this means that region a is the solution.

step-by-step explanation:

mark brainliest!

30.5*10=350$

you have to multiply the number without the decimal point then add it later but if its tenn u must move the place value of the decimal point 1 to the right.