Damell is training for a marathon and expects to run at a constant rate for the entire race. If it takes Damell 3 hours to run 15 miles, how long will it take Damell to run 55 miles?

11 hours

Step-by-step explanation:

If Damell is running at a constant rate, we can create a direct proportionality statement, where when one variable (let's call it the mileage, 15 miles) increases, the other also increases (the time, 3 hours). And vice versa.

Written as a direct proportionality statement, let's call it:

time/mileage = time 2.0/mileage 2.0

time = 3

mileage = 15

time 2.0 = x

mileage 2.0 = 55

This would give us something like:

3/15 = x/55 <--- Hey! Fractions!

If we simplify, this is 1/5 = x/55.

Now we should find out how to make both denominators equal (so we have to find the LCM). The LCM of 55 and 5 is 55 (since 5 is a multiple of 55). Therefore, by just multiplying the numerator and denominator of 1/5, we get 11/55.

Now, we have 11/55 = x/55

Since the denominators match, we now know that 11/55 and x/55 are the same fraction. Therefore, the numerators are the same: 11 and x.

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°

37 = ending with 7

unit's digit in the cube..3

56 = ending with 6

unit's digit in the cube..2

133 = ending with

unit's digit in the cube..7

hope it : ( : )