36. If the area of a rectangular field is is 28x* - 56x and one of its side is 7x, what is its other side? SECTION - E 4X1=4M

The area of a rectangular field is 28x^2-56x square units and one of its side is 7x units.

The other side of the rectangular field.

Area of the rectangular field = 28x^2-56x square units

Let its length be 7x units.

We know, area of a rectangle = length × breadth

So, breadth = area ÷ length

Therefore, the breadth of the rectangular field

The other side of the rectangular field is 4x-8 units.

the value of v.w= -12.

step-by-step explanation:

we are given three vector r,v and w as:

r = < 5, -5, -2> ; v = < 2, -8, -8> ; w = < -2, 6, -5>

we know that r,v and w could also be represented as:

r=5i-5j-2k

v=2i-8j-8k

and w= -2i+6j-5k

where i,j and k are the unit vectors of x,y and z-axis respectively.

also we know that it has the following property:

i.i=1 ; j.j=1; k.k=1

and i.=j.i=i.k=k.i=j.k=k.j=0

i.e. when we multiply two vectors or we find it's dot product we need to only multiply the components of x coordinates with each other; y with each other and z with each other.

hence, v.w= (2i-8j- -2i+6j-5k)

                  = 2×(-2)+(-8)×(6)+(-8)×(-5)

                  = -4-48+40

                  = -12

hence, v.w= -12

i would say b) is your answer

sorry if im wrong

step-by-step explanation: