jane has a ton of 5p and 2p coins. if she takes 4 coins how many different totals could she have? i’ll pick brainiest to whoever gets it right :)

5

Step-by-step explanation:

Im not sure if this is correct but i think the question is asking forehow many combinations there can be. you can have 5555, 5552, 5522, 5222, or 2222.

that means 5 combinations.

however, if the order of numbers in the combinations matter, which i dont think it does, there can be many more combinations. 5555, 2555, 5255, 5525, 5552, 2255, 2525, 2552, 2252, 2522, 2222. i think thats all the combinations

this adds up to 11 combinations

i hope this helps. im sorry if it didnt

the answer is two. hope this !

find the vertical and horizontal asymptotes of the function f x = 5 x − 1 . to find the vertical asymptote, equate the denominator to zero and solve for . since the degree of the polynomial in the numerator is less than that of the denominator, the horizontal asymptote is .

step-by-step explanation: