PLEASEEE I NEED HELPPP Find a point-slope form for the line that satisfies the stated conditions.
Slope 5, passing through ( -4 , 2 )

and please dont just answer for points... i really need helppp

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Find a point-slope form for the line that satisfies the stated conditions. Slope , passing through (-5,4)

I really need this question answered

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I don't see a value for the slope. We need that to set the equation, otherwise I can write an unlimited number of equations that pass through (-5,4).

I'll assume a slope so that you can see how the procedure would work. I like 6, so we'll assume a slope of 6.

The equation for a straight line has the form y = mx + b, where m is the slope and y is the y-intercept, the value of y when x = 0. We want a line that has slope 6, so:

y = 6x + b

We need to find b, so substitute the point (-5,4) that we know is on the line:

4 = 6*(-5) + b and solve for b

4 = -30 + b

b = 34

The line is y = 6x + 34

d

step-by-step explanation:

d

∠acb = 8°

step-by-step explanation:

∠xba lies on the circle and is half the measure of the intercepted arc ax

hence

measure of arc ax = 2 × 42° = 84°

∠acb is outside the circle and is

∠acb = (arcab - arcax ), hence

∠acb = 0.5 (100 - 84) = 0.5 × 16° = 8°