the first term of an arithmetic sequence is 8, the last term id 56 and the sum is 416. find the number of terms

13

Step-by-step explanation:

first term (a) = 8

last term ( ) = 56

sum (S) = 416

number of terms (n) = ?

                              equation

                              S = n/2 (a+)

                             416 = n/2 (8+56)

                             416 = n/2 (64)

                              416 = 32n

                               n = 416/32 = 13

d. 8

step-by-step explanation:

the given radical expression is:

we can rewrite this as:

we express as square numbers to get;

the exponents will now cancel out to give.

the correct answer is d

13.46

step-by-step explanation:

16.80 x .20 = 13.46