Ss Math 1S1C Full Semester - 2021 Subtracting Fractions
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Conversion a mixed number 1 2/

3

to a improper fraction: 1 2/3 = 1 2/

3

= 1 · 3 + 2/

3

= 3 + 2/

3

= 5/

3

To find new numerator:

a) Multiply the whole number 1 by the denominator 3. Whole number 1 equally 1 * 3/

3

= 3/

3

b) Add the answer from previous step 3 to the numerator 2. New numerator is 3 + 2 = 5

c) Write a previous answer (new numerator 5) over the denominator 3.

One and two thirds is five thirds

Conversion a mixed number 2 1/

3

to a improper fraction: 2 1/3 = 2 1/

3

= 2 · 3 + 1/

3

= 6 + 1/

3

= 7/

3

To find new numerator:

a) Multiply the whole number 2 by the denominator 3. Whole number 2 equally 2 * 3/

3

= 6/

3

b) Add the answer from previous step 6 to the numerator 1. New numerator is 6 + 1 = 7

c) Write a previous answer (new numerator 7) over the denominator 3.

Two and one third is seven thirds

Subtract: 5/

3

- 7/

3

= 5 - 7/

3

= -2/

3

For adding, subtracting, and comparing fractions, it is suitable to adjust both fractions to a common (equal, identical) denominator. The common denominator you can calculate as the least common multiple of both denominators - LCM(3, 3) = 3. In practice, it is enough to find the common denominator (not necessarily the lowest) by multiplying the denominators: 3 × 3 = 9. In the next intermediate step, the fraction result cannot be further simplified by canceling.

In words - five thirds minus seven thirds = minus two thirds.

solution:

→c= a b , that is product of a and b is possible only when when a is m × n matrix and b is n × p matrix.

that is, number of columns of a= number of rows of b.

so, size of matrix , c= a b is , if a = (m × n)matrix

b= (n × p)matrix

then a b = [ (m × n)matrix] ×[   (n × p)matrix ]

→→c= a b= [m × p ] matrix

→→size of product a b will be equal to = number of rows of a × number of columns of b

step-by-step explanation: