If f(x) = 3x^2 - 1 and g(x) = 4x + 2, then what is f(g(x))?

(f + g) (2) = -4(f+g)(2)=−4

Step-by-step explanation:

We have the functions

F(x) =-3x^2-2F(x)=−3x2−2   And  g(x)=4x+2g(x)=4x+2

We want to find

(f + g) (x)(f+g)(x)

Then

\begin{gathered}(f+g)(x) = f(x) + g(x)(f+g)(x) = -3x^2-2 + 4x+2(f+g)(x)= -3x^2 +4x\end{gathered}(f+g)(x)=f(x)+g(x)(f+g)(x)=−3x2−2+4x+2(f+g)(x)=−3x2+4x

finally we find

(f + g) (2)(f+g)(2)

\begin{gathered}(f + g) (2) = -3(2)^2 + 4(2)(f + g) (2) = -3*4 + 8(f + g) (2) = -12+ 8(f + g) (2) = -4\end{gathered}(f+g)(2)=−3(2)2+4(2)(f+g)(2)=−3∗4+8(f+g)(2)=−12+8(f+g)(2)=−4

d

step-by-step explanation:

in a an geometric explicit equation, the first number is the starting rate. in this case 10.

the least common denominator is 40