HELP PLEASE!!! Assume that when adults with smartphones are randomly selected, 59 % use them in meetings or classes. If 15 adult smartphone users are randomly selected, find the probability that exactly 10 of them use their smartphones in meetings or classes.
The probability is ?

5/10

Step-by-step explanation:

Let X will be the number of adults with smartphone which use them in meetings or classes.

X~Binomial(15, 0.59)

P(X=x) = C^{15}_x(0.59)^x(1-0.59)^{15-x}P(X=x)=C

x

15

(0.59)

x

(1−0.59)

15−x

You have to find the probability that exactly 10 of them use their smartphones in meetings or classes.

P(X=10) = C^{15}_{10} (0.59)^{10} (1-0.59)^{15-10} \\ = \frac{15!}{10!(15-10)!}(0.59)^{10}(0.41)^5 \\ = 3003 \times 0.00511 \times 0.01158 \\ = 0.17782P(X=10)=C

10

15

(0.59)

10

(1−0.59)

15−10

=

10!(15−10)!

15!

(0.59)

10

(0.41)

5

=3003×0.00511×0.01158

=0.17782

P=0.17782

answer: i don't understand. what are the options

step-by-step explanation: