The table below shows the estimated population of fish living in the local lake as determined by the local environmental council every 10 years between 1960 and 1990. The equation y = 1500(0.9)x describes the curve of best fit for the fish population (y). Let x represent the number of 10-year intervals since 1960. Year Population
1960 1500
1970 1350
1980 1210
1990 1100
Using this equation, what is the approximate predicted population of fish living in the lake in the year 2020?

answer: 1,380

step-by-step explanation:

1: you turn %15 into a decimal by moving the decimal point two places to the left.

2: and then you multiply .15 by 1,200 , which will get you 180.00

3: from there you will add 180 to 1,200

4: which will get you 1,380

hope it *im kind of slow so idk if my answer is right*

3 qrs + 3/2 xy hope this : /

step-by-step explanation:

here's a poem i finished a while ago. i hope you like it and that it inspires you.

the answer is a. 72. but i cant answer with less than 20 characters so here's some random text talking about it.