Find three consecutive integers such that the sum of the first and third is 40

The three consecutive integers are 19, 20, and 21. And 19 + 21 = 40.

Step-by-step explanation:

Let the first integer be x.

The next consecutive integer would be x + 1 and the next x + 2.

The equation for the sum of the first and third integer equaling 40 can then be written as:

x + (x + 2) = 40

Solving gives:

2x + 2 = 40

2x + 2 - 2 = 40 - 2

2x = 38

x = 19