1. Which are the values of a, b, and c in the quadratic equation 8x^2 + 5x + 2 = 0? a=8, b = 2, c=5
a=2, b = 5, c= 8
a=2, b = 8, c=5
a = 8, b = 5, c= 2

yes because there is exactly one y value for every x value

for function there can't be more than one value for every x value

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116