d) 21 (1 g) x (x - y) 1) - 3pq (2p + 79) m) - 8x (x2 – 2x + 1) h) 4xy (2x + 3y) i) 2ab (5a? - 4b- k) – 2bc (9b - 50) 1) – 5xy (3x2 – 6y) n) - 7a (2a2 + 30 - 5) 0) – 2xy (3x – 5x – 4y") TC 3 and 1 = 2a show that xy = 2a2 + 6a

tangent

step-by-step explanation:

b. x + 1

step-by-step explanation:

i'am smart

b

step-by-step explanation:

the equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

calculate m using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (0, 4) and (x₂, y₂ ) = (3, - 5) ← 2 points on the line

m = = = - 3

with m = - 3 and (a, b) = (3, - 5), then

y - (- 5) = - 3(x - 3), that is

y + 5 = - 3(x - 3) → b