Find three solution of the equation: 2x + y = 7.​

Step-by-step explanation:

2x+y=7

(A) (0,7),(72,0)and(3,1)

(B) (0,6),(72,0)and(3,1)

(C) (0,7),(52,0)and(3,1)

(D) (0,7),(72,0)and(2,1)

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Find three solutions of the equation: 2x+y=7

(A) (0,7),(72,0)and(3,1)

(B) (0,6),(72,0)and(3,1)

(C) (0,7),(52,0)and(3,1)

(D) (0,7),(72,0)and(2,1)

Given:

The linear equation having variables x and y is given as –

2x+y=7

For the initial solution of the equation, put x=0 in the linear equation and obtain the value of variable y .

So, substituting x=0 in the equation, we get,

2×0+y=7y=7

So, the first solution of the linear equation is

x=0

y=7

In two-dimensional coordinates form (x,y) , the first solution is (0,7) .

Now, similarly,

Substituting y=0 in the linear equation we have,

⇒2x+0=7⇒2x=7⇒x=72

So, the second solution of the linear equation is

x=72

y=0

In two-dimensional coordinates form (x,y) , the second solution is (72,0) .

And finally,

Substituting y=1 in the linear equation we have,

⇒2x+1=7⇒2x=6⇒x=62⇒x=3

So, the third solution of the linear equation is

x=3

y=1

In two-dimensional coordinates form (x,y) , the third solution is (3,1) .

Therefore, the three solutions of the equation 2x+y=7 are (0,7) , (72,0) and (3,1) .

The correct answer is –

(A) (0,7),(72,0)and(3,1)

Therefore, the three solutions of the equation 2x+y=7 are (0,7) , (72,0) and (3,1) . So, the correct answer is “Option A”.

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