Two cars are 400 km apart. One car is traveling at 55 km/h and the other car is traveling at 45 km/h. If they start at the same time and are driving toward each other, how long will it take them to meet? A)3 hours B)4 hours C)5 hours D)6 hours

Two cars are 400 km apart. One car is traveling at 55 km/h, and the other cars are traveling at 45 km/h; if they start at the same time and are driving toward each other, the two cars will meet after 4 hours.

Solution:

Let the two-car be A and B.

Given that two cars are 400 km apart.  

Let us assume The distance traveled by A to meet B = x km.

The distance traveled by B can be found by subtracting the total distance x from a length is traveled by A.

So distance travelled by B = (400-x) km

Time taken will be the same for A and B

We know that,  we get

Let us consider the time taken by car. So time is taken by A to travel x km =

Similarly, time is taken by B to travel distance (400-x) km =  

When the two cars meet, .hence we get,

On solving above equation,

9x = 11(400 – x)

9x = 4400 – 11x

9x + 11x = 4400

20x = 4400

X = 220

After 220 km of travel, the car with a speed of 55 km will meet other cars traveling at a rate of 45 km. Now the time taken for two cars to meet each other is given as,

Time is taken for cars to meet =  

Hence the two cars will meet after 4 hours.

Step-by-step explanation:

step-by-step explanation:

quartic functions has x = –1 and x = –2 as its only two real zeroes:

f(x) = a(x+2)(x+1)   a: real number

idk

step-by-step explanation: