The complex number 16 has the following roots calculated. 1st root (k = 0): 2 left-bracket cosine (StartFraction 0 pi Over 4 EndFraction) I sine (StartFraction 0 pi Over 4 EndFraction right-bracket 2nd root (k = 1): 2 left-bracket cosine (StartFraction 2 pi Over 4 EndFraction) I sine (StartFraction 2 pi Over 4 EndFraction right-bracket 3rd root (k = 2): 2 left-bracket cosine (StartFraction 4 pi Over 4 EndFraction) I sine (StartFraction 4 pi Over 4 EndFraction right-bracket

What is the 4th root (k = 3) of 16?

the answer is b im just adding this for others to find

answer:

1. 0.04

2. 0.15

step-by-step explanation:

i just finished that assignment for properties of probability distributions.

σк тнє αиѕωєя ιѕ (α.)

нσρє ι ¢συℓ∂ нєℓρ υ

there is only one way to arrange all the eight relative to each other because they are not distinct. we have

now there are nine places to place an (and not more than one in one place).   because we have four symbols, we need to choose four of these nine places to insert an . order does not matter because the are not distinct.

thus there are 1 · c(9,4) ways, or, if we calculate it,

thus there are 126 ways to form such "words."