Find two consecutive odd integers such that 28 more than the lesser is three times the greater. The lesser consecutive odd integer is , and the greater consecutive odd integer is

lesser odd integer =11

Greater odd integer=13

Step-by-step explanation:

let the consecutive odd integers be x,x+2

and  x<x+2

3(x+2)=x+28

3x+6=x+28

3x-x=28-6

2x=22

x=11

x+2=11+3=13

b. ol

step-by-step explanation:

i got the answer right on edg.

congruent: (geometry) (of figures) identical in form; coinciding exactly when superimposed.

step-by-step explanation: