Shown above is the graph of the differentiable function f, along with the line tangent to the graph of f at x=2. What is the value of f′(2) ?

f'(2) means "the slope of the tangent line to y=f(x) when x=2".

Since that tangent line is drawn, this is really asking, "What's the slope of that line?"

So, what's the rise/run for that line?

1; 35 is the ratio

step-by-step explanation:

96 39 cause 135 -96=39 im smart (i used a calculater)