PLEASE PLEASE PLEASE HELP ASAP! a car having a mass of 1,750 kg travels 10 kilometers to the grocery store. Which mathematical expression can be used to calculate the acceleration if the cae has a net force of 3,500 n acting on it?

F. 35,000 N/1,750 kg

G. 1,750 kg x 35,000 N

H. 1,750 kg/35,000 N

J. 1,750+35,000 N

1 thanks,5 star, and brainlist for correct answers

F

Step-by-step explanation:

if F=ma

then F=35000, M=1750, A=?

make a the subject

a=F/m

a = 35,000/1,750

CLEAR!!!

6.9

step-by-step explanation:

simple math really

6 1/2 times 0.6 = 3.9

but if you are just doing 6 and not 6 1/2 then the answer is 3.6

this is a direct variation proportion. y = kx

y is the total amount due, k is the constant of variation, and x is the number of texts sent.

plug in the 3.20 and the 16 to solve for the "k". this is the constant of proportionality. it is the value that will not change.

3.20 = k(16). solving you get $.20 per text.

the equation would then be y = .20x