7^2 times 7^8 / 7^4 =7^a /7^4 =7^b what does a and b equal ?

a = 10

b = 6

Step-by-step explanation:

(7^2 * 7^8) / 7^4 = 7^a / 7^4

7^2 * 7^8 = 7^10

7^10 / 7^4 = 7^a / 7^4

7^10 = 7^a

a = 10

7^a / 7^4 = 7^b

7^10 / 7^4 = 7^10-4

7^6 = 7^b

b = 6

(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180 

same as (2x + 16) + (x) = 180