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Mathematics, 18.09.2021 05:30 obryonshaniya10

The repeating decimal 0.5333... is equal to 815 8
15
. Which equation shows a method to find the fraction equal to 0.5533?

0.5533...=0.5333...+0.02=815
+15
=1115
, 0.5533...=0.5333...+0.02=8 over 15+1 fifth=11 over 15

0.5533...=0.5333...+0.02=815
+150
=965
, 0.5533...=0.5333...+0.02=8 over 15+1 over 50=9 over 65

0.5533...=0.5333...+0.02=815
+115
=920
, 0.5533...=0.5333...+0.02=8 over 15+1 over 15=9 over 20

0.5533...=0.5333...+0.02=815
+150
=83150 my

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Answers: 1

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The repeating decimal 0.5333... is equal to 815 8
15
. Which equation shows a method t...
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