While visiting a friend's home, I saw kittens and children playing in the backyard. Counting heads, I got 11. Counting feet, I got 32. How many kittens and how many children were in the backyard? (Hint: Use a
Variable)

5 kittens and 6 children

Step-by-step explanation:

We can use variables to find the number of kittens (K) and children (C)

each kitten will have 4 legs and each child will have 2.

You can make two equations like so:

4k+2c=32

k+c=11

You then can use the substitution method to solve for both variables:

k+c=11

Subtract k from each side:

c=11-k

Substitute this into the other equation:

4k+2(−k+11)=32

Solve for k:

4k-2k+22=32

2k=10

k=5

Then use this in one of the equations to find the other variable:

k+c=11

5+c=11

Rewrite this to make it easier:

11-5=c

c=6

k=5 and c=6

you can check this by substituting each of these value to make sure the equations are true:

k+c=11

5+6=11

11=11

4k+2c=32

4(5)+2(6)=32

20+12=32

32=32

They both check right, so

c=6 and k=5

are your answers.

There are 5 kittens and 6 children in the backyard

There is your answer

Hope this helps!

answer rather than having to add and subtract the measurements of the semi-circle, notice that the semicircle to the left of ad is actually identical in area to the blank semicircle-shaped space to the left of bc. so if we transferred the red semicircle into the blank space, we would end up with a square of side length 24 cm. the area of a square is s^2 = 24^2 = 676 cm^2.

u also answered this so i think u would know but i am here to

put in or use mine