An object thrown in the air has a velocity after seconds that can be described by v(t) = - 9.8z + 24(m) meters/second) and a height h(t) = - 4.9t ^ 2 + 2t + 60 in meters). The object has n = 2 kilograms. The kinetic energy of the shirst is given by K= 1 2 mr^ 2 , and the potential energy is given by 19.5mh. Find an expression for the total kinetic and potential energy K+ U as a functim of time. What does this expression tell you about the energy of the falling object?

3

step-by-step explanation:

because where the point where the 2 lines intersect is (3,-1) the x value is 3

b, 20 yards

step-by-step explanation:

the answer would be 0.54

18 units²

step-by-step explanation:

first let's find altitude bd using the distance formula

d = √((y₂ - y₁)² + (x₂ - x₁)²)

bd = √((0 - -3)² + (0 - 3)²)

bd = √18

given the placement of points a and c, we can denote that point d bisects segment ac.

we will call ac the base.

using the distance formula

ac = √((0 - 6)² + (-6 - 0)²)

ac = √72

knowing our base and our height, we can plug these into our triangle area formula

area = (b * h)/2

area = (√18 * √72) / 2

area = (√1296) / 2

area = 36 / 2

area = 18 units²