I'm doing a precal test right now please help What is the slope of the line that passes through the points (-7,-3) and (-2,6)​

1.8

Step-by-step explanation:

(x1,y1)= (-7, -3) & (x2, y2) = (-2,6)

slope = (y2-y1)/(x2-x1) = (6-(-3))/(-2-(-7)) = (9)/(5)= 1.8

b

step-by-step explanation:

the equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

calculate m using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (0, 4) and (x₂, y₂ ) = (3, - 5) ← 2 points on the line

m = = = - 3

with m = - 3 and (a, b) = (3, - 5), then

y - (- 5) = - 3(x - 3), that is

y + 5 = - 3(x - 3) → b

explanation:

remove parenthesis:

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apply rule

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multiply fractions:

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divide:

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mordancy.