I'm doing a precal test right now please help find a slope-intercept form equation for the line.
through the points (1,6) and (-1,9)​

Since slope of line passing through two points (x

1

,y

1

) and (x

2

,y

2

) is m=

x

2

−x

1

y

2

−y

1

We now find the slope of the line passing through the points (2,3) and (4,6) as shown below:

m=

4−2

6−3

=

2

3

Therefore, the slope of the line is

2

3

.

Now use the slope and point (2,3) to find the y-intercept.

y=mx+b

⇒3=(

2

3

×2)+b

⇒3=3+b

⇒b=3−3=0

Write the equation in slope intercept form as:

y=mx+b

⇒y=

2

3

x+0

⇒y=

2

3

x

Hence, the equation of the line is y=

2

3

x..

step-by-step explanation:

3

step-by-step explanation:

because where the point where the 2 lines intersect is (3,-1) the x value is 3