A line with a slope of 1/6 passes through the point (-6, 5). What is its equation in slope-intercept form?

y=1/6x+6

Step-by-step explanation:

hello i put this equation into graph and it matches

#(-6,5), (x,y)€L(line) and m=1/6 by point-slope form of equation of a line, the equation becomes; 1/6=y-5/x-(-6)

x+6=6y-30

x-6y+36=0(point-slope form)

but since we are asked to find in slope-intercept form and we have slope(m)=1/6 and y-intercept(b)=36/6=6

then y=1/6x+b or y=1/6x+6 is its slope-intercept form.

answer with step-by-step explanation:

a. ∠j is supplementary to ∠k - true:

(opposite angles of a trapezoid are supplementary which means that they add up to 180 degrees)

b. kl is parallel to jm - true:

(opposite sides are parallel to each other in a trapezoid)

c. jk is perpendicular to kl - false:

(clearly, jk does not make a right angle with kl)

d. jk is parallel to lm - false:

(jk and lm are two lines opposite in direction to each other so they cannot be parallel)

e. ∠j is congruent to ∠m - true:

(the angles on each side of the base are congruent)

f. ∠j is congruent to ∠k - false:

(the angles on the same side but opposite side of the base are not congruent)

step-by-step explanation:

y = | -2(-2) |     →     y = | 4 |     →     y = 4       ⇒   (-2, 4)

y = | -2(-1) |     →     y = | 2 |     →       y =   2       ⇒   (-1, 2)    

y = | -2(0) |     →     y = | 0 |     →       y = 0         ⇒   (0, 0)

y = | -2(1) |   c →     y = | -2 |     →     y =   2         ⇒   (1, 2)    

y = | -2(2) |     →     y = | - 4 |     →     y =   4         ⇒   (2, 4)