A sequence of two transformations that can be used to show that polygon ABCDE is congruent to polygon GFJIH is _ followed by _. option for #1: (a) a reflection across the x-axis. (b) a translation 2 units down. (c) a 90 degree counterclockwise rotation about point D. option for #2: (a) a 90 degree clockwise rotation about point D. (b) a reflection across the y-axis. (c) a translation 2 units left.

6hryt%4578855

answer: plz put a pic in so i can answer it

step-by-step explanation:

c. 27 units.

step-by-step explanation:

we are told that in circle a, ∠bae ≅ ∠dae.

we can see from our given diagram that in and ;

, as these are radii of our given circle.

therefore, by sas congruence postulate.

hence, side be will be equal to side de as corresponding parts of congruent triangles are congruent. so we can set an equation to find the value of x as:

now let us substitute x=17 in the expression for the length of be.

therefore, length of be will be 27 units and option c is the correct choice.