How many 3 digit codes are possible that do not contain the number 3?

729

Step-by-step explanation:

Including 3, there are 10 digits, from 0 to 9.

If you exclude 3, then there are 9 digits.

Each code will have a first digit, a second digit, and a third digit.

Each of those three digits can be chosen from 9 different digits.

We use the counting principle, and we multiply the number of possible digits for each position in the code.

number of possible first digits * number of possible second digits * number of possible third digits =

= 9 * 9 * 9 = 729

729

the answer is simply just 6n add the two together as they have an n