The sum of three numbers is 74. The third number is 2 times the first. The second number is 10 less than the first what are the numbers First number:
Second number:
Third number:

Step-by-step explanation:

let the 1st number be x

given,

2nd number = 10 less than 1st number = x - 10

3rd number = 2 times the 1st number = 2x

their sum = 74

a/q,

x + x - 10 + 2x = 74

after solving the equation,

→ x + x - 10 + 2x = 74

→ 4x - 10 = 74

→ 4x = 74 + 10 = 84

→ 4x = 84

→ x = 84/4 = 21

therefore,

1st number = x = 21

2nd number = 10 - x = 21 - 10 = 11

3rd number = 2x = 2 × 21 = 42

hope this answer helps you deartake care and may u have a great day ahead!

example 2 – simplify: step 1: completely factor both the numerators and denominators of all fractions. step 2: change the division sign to a multiplication sign and flip (or reciprocate) the fraction after the division sign; essential you need to multiply by the reciprocal. step 3 : cancel or reduce the fractions.

5+2x=a

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