Find the x-intercept and y-intercept of the line . 7/3x - 1/3y = 1​

Step-by-step explanation:

The general equation of a line is y = mx+b

Rewrite the given equation (7/3)x -(1/3)y = 1 in the form of the general equation y=mx+b, where b is the y-intercept.

(7/3)x -(1/3)y = 1

-(1/3)y = -(7/3)x +1 , subtract (7/3)x from both sides

(1/3)y = (7/3)x -1 , multiplyed both sides by (-1)

y= 3(7/3)x -3, multiply both sides by 3

y= 7x -3, so

y-intercept is -3 or you can say that the y-intercept is at point (0, -3)

The x -intercept is at point (something, 0) so our y coordinate is 0 there

y= 7x -3, yet y=0 we said so substitute y with 0 in the equation and find x

0=7x-3 , add 3 to both sides

3= 7x, divide both sides by 7

3/7 = x

x-intercept is 3/7 or you can say that the x-intercept is at point (3/7, 0)

the square root of what number? if you add that, then someone will probably answer the question.

dalila is incorrect. the whisker on the left is very long, going all the way out to 5. the whisker goes from 5 to 30, so it has a spread of 25. the rest of the box plot values are closer together, so 5 is an outlier