Given that f(x)=2x+3 and g (x)=x^2-4x-5, find (g o f)(6)

160

Step-by-step explanation:

g(f(6))=?

f(6) = 2*6+3=15

g(15) = 15*15 - 4*15 -5 =160

no oblique asymptote

step-by-step explanation:

to find the oblique asymptote of f(x)

here numerator has degree 1 and denomintor degree 2

degree of numerator < degree of denominator

hence there is no oblique asymptote

when the degree of the denominator > that of the numerator, we saw that the value in the denominator got so much bigger, so quickly,   giving us a horizontal asymptote of the x-axis. or we can write

f(x) = a polynomial of x + a proper fraction.

in this case only we have oblique asymptotes but not when numerator has less degree.